Solve (80-2*131/3)*131/3

$$(80-2 \times 13 \frac { 1 } { 3 } ) \times 13 \frac { 1 } { 3 }$$

Evaluate

$$\frac{6400}{9}\approx 711.111111111$$

Solution Steps

Multiply 13 and 3 to get 39.

$$\left(80-2\times \frac{39+1}{3}\right)\times \frac{13\times 3+1}{3}$$

Add 39 and 1 to get 40.

$$\left(80-2\times \frac{40}{3}\right)\times \frac{13\times 3+1}{3}$$

Express 2\times \frac{40}{3} as a single fraction.

$$\left(80-\frac{2\times 40}{3}\right)\times \frac{13\times 3+1}{3}$$

Multiply 2 and 40 to get 80.

$$\left(80-\frac{80}{3}\right)\times \frac{13\times 3+1}{3}$$

Convert 80 to fraction \frac{240}{3}.

$$\left(\frac{240}{3}-\frac{80}{3}\right)\times \frac{13\times 3+1}{3}$$

Since \frac{240}{3} and \frac{80}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{240-80}{3}\times \frac{13\times 3+1}{3}$$

Subtract 80 from 240 to get 160.

$$\frac{160}{3}\times \frac{13\times 3+1}{3}$$

Multiply 13 and 3 to get 39.

$$\frac{160}{3}\times \frac{39+1}{3}$$

Add 39 and 1 to get 40.

$$\frac{160}{3}\times \frac{40}{3}$$

Multiply \frac{160}{3} times \frac{40}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{160\times 40}{3\times 3}$$

Do the multiplications in the fraction \frac{160\times 40}{3\times 3}.

$$\frac{6400}{9}$$

Factor

$$\frac{2 ^ {8} \cdot 5 ^ {2}}{3 ^ {2}} = 711\frac{1}{9} = 711.1111111111111$$