Solve (7^circ8-3^circ7)-(-9^circ7-3)-(-15-10)+6=

$$(7 ^ { \circ } 8-3 ^ { \circ } 7)-(-9 ^ { \circ } 7-3)-(-15-10)+6=$$

Evaluate

$$132$$

Solution Steps

Multiply 7 and 8 to get 56.

$$56-3\times 7-\left(-9\times 7-3\right)-\left(-15-10\right)+6$$

Multiply 3 and 7 to get 21.

$$56-21-\left(-9\times 7-3\right)-\left(-15-10\right)+6$$

Subtract 21 from 56 to get 35.

$$35-\left(-9\times 7-3\right)-\left(-15-10\right)+6$$

Multiply -9 and 7 to get -63.

$$35-\left(-63-3\right)-\left(-15-10\right)+6$$

Subtract 3 from -63 to get -66.

$$35-\left(-66\right)-\left(-15-10\right)+6$$

The opposite of -66 is 66.

$$35+66-\left(-15-10\right)+6$$

Add 35 and 66 to get 101.

$$101-\left(-15-10\right)+6$$

Subtract 10 from -15 to get -25.

$$101-\left(-25\right)+6$$

The opposite of -25 is 25.

$$101+25+6$$

Add 101 and 25 to get 126.

$$126+6$$

Add 126 and 6 to get 132.

$$132$$

Factor

$$2^{2}\times 3\times 11$$