Solve (5-3*4)+12*2div3-9div2*3+7%4*3

$$(5-3 \times 4)+12 \times 2 \div 3-9 \div 2 \times 3+7 \% 4 \times 3$$

Evaluate

$$-\frac{583}{50}=-11.66$$

Solution Steps

Multiply 3 and 4 to get 12.

$$5-12+\frac{12\times 2}{3}-\frac{9}{2}\times 3+\frac{7}{100}\times 4\times 3$$

Subtract 12 from 5 to get -7.

$$-7+\frac{12\times 2}{3}-\frac{9}{2}\times 3+\frac{7}{100}\times 4\times 3$$

Multiply 12 and 2 to get 24.

$$-7+\frac{24}{3}-\frac{9}{2}\times 3+\frac{7}{100}\times 4\times 3$$

Divide 24 by 3 to get 8.

$$-7+8-\frac{9}{2}\times 3+\frac{7}{100}\times 4\times 3$$

Add -7 and 8 to get 1.

$$1-\frac{9}{2}\times 3+\frac{7}{100}\times 4\times 3$$

Express \frac{9}{2}\times 3 as a single fraction.

$$1-\frac{9\times 3}{2}+\frac{7}{100}\times 4\times 3$$

Multiply 9 and 3 to get 27.

$$1-\frac{27}{2}+\frac{7}{100}\times 4\times 3$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}-\frac{27}{2}+\frac{7}{100}\times 4\times 3$$

Since \frac{2}{2} and \frac{27}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-27}{2}+\frac{7}{100}\times 4\times 3$$

Subtract 27 from 2 to get -25.

$$-\frac{25}{2}+\frac{7}{100}\times 4\times 3$$

Express \frac{7}{100}\times 4 as a single fraction.

$$-\frac{25}{2}+\frac{7\times 4}{100}\times 3$$

Multiply 7 and 4 to get 28.

$$-\frac{25}{2}+\frac{28}{100}\times 3$$

Reduce the fraction \frac{28}{100} to lowest terms by extracting and canceling out 4.

$$-\frac{25}{2}+\frac{7}{25}\times 3$$

Express \frac{7}{25}\times 3 as a single fraction.

$$-\frac{25}{2}+\frac{7\times 3}{25}$$

Multiply 7 and 3 to get 21.

$$-\frac{25}{2}+\frac{21}{25}$$

Least common multiple of 2 and 25 is 50. Convert -\frac{25}{2} and \frac{21}{25} to fractions with denominator 50.

$$-\frac{625}{50}+\frac{42}{50}$$

Since -\frac{625}{50} and \frac{42}{50} have the same denominator, add them by adding their numerators.

$$\frac{-625+42}{50}$$

Add -625 and 42 to get -583.

$$-\frac{583}{50}$$

Factor

$$-\frac{583}{50} = -11\frac{33}{50} = -11.66$$