Solve (4x-2x/2-x)

$$(4x- \frac{ 2x }{ 2-x } )$$

Evaluate

$$\frac{2x\left(3-2x\right)}{2-x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 4x times \frac{2-x}{2-x}.

$$\frac{4x\left(2-x\right)}{2-x}-\frac{2x}{2-x}$$

Since \frac{4x\left(2-x\right)}{2-x} and \frac{2x}{2-x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4x\left(2-x\right)-2x}{2-x}$$

Do the multiplications in 4x\left(2-x\right)-2x.

$$\frac{8x-4x^{2}-2x}{2-x}$$

Combine like terms in 8x-4x^{2}-2x.

$$\frac{6x-4x^{2}}{2-x}$$

Factor

$$\frac{2x\left(3-2x\right)}{2-x}$$