Solve (4-3)*(4^2)-4^3-3(4^2)

$$(4-3) \times ( { 4 }^{ 2 } )- { 4 }^{ 3 } -3( { 4 }^{ 2 } )$$

Evaluate

$$-96$$

Solution Steps

Subtract 3 from 4 to get 1.

$$1\times 4^{2}-4^{3}-3\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$1\times 16-4^{3}-3\times 4^{2}$$

Multiply 1 and 16 to get 16.

$$16-4^{3}-3\times 4^{2}$$

Calculate 4 to the power of 3 and get 64.

$$16-64-3\times 4^{2}$$

Subtract 64 from 16 to get -48.

$$-48-3\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-48-3\times 16$$

Multiply 3 and 16 to get 48.

$$-48-48$$

Subtract 48 from -48 to get -96.

$$-96$$

Factor

$$-96$$