Solve for x
x<8
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3x-4<\frac{32}{1.6}
Divide both sides by 1.6. Since 1.6 is positive, the inequality direction remains the same.
3x-4<\frac{320}{16}
Expand \frac{32}{1.6} by multiplying both numerator and the denominator by 10.
3x-4<20
Divide 320 by 16 to get 20.
3x<20+4
Add 4 to both sides.
3x<24
Add 20 and 4 to get 24.
x<\frac{24}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
x<8
Divide 24 by 3 to get 8.
Examples
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}