Solve (35+25+45+55+35+3+6+5+4+4+5+3+7+5+6)div15

$$(35+25+45+55+35+3+6+5+4+4+5+3+7+5+6) \div 15$$

Evaluate

$$\frac{81}{5}=16.2$$

Solution Steps

Add 35 and 25 to get 60.

$$\frac{60+45+55+35+3+6+5+4+4+5+3+7+5+6}{15}$$

Add 60 and 45 to get 105.

$$\frac{105+55+35+3+6+5+4+4+5+3+7+5+6}{15}$$

Add 105 and 55 to get 160.

$$\frac{160+35+3+6+5+4+4+5+3+7+5+6}{15}$$

Add 160 and 35 to get 195.

$$\frac{195+3+6+5+4+4+5+3+7+5+6}{15}$$

Add 195 and 3 to get 198.

$$\frac{198+6+5+4+4+5+3+7+5+6}{15}$$

Add 198 and 6 to get 204.

$$\frac{204+5+4+4+5+3+7+5+6}{15}$$

Add 204 and 5 to get 209.

$$\frac{209+4+4+5+3+7+5+6}{15}$$

Add 209 and 4 to get 213.

$$\frac{213+4+5+3+7+5+6}{15}$$

Add 213 and 4 to get 217.

$$\frac{217+5+3+7+5+6}{15}$$

Add 217 and 5 to get 222.

$$\frac{222+3+7+5+6}{15}$$

Add 222 and 3 to get 225.

$$\frac{225+7+5+6}{15}$$

Add 225 and 7 to get 232.

$$\frac{232+5+6}{15}$$

Add 232 and 5 to get 237.

$$\frac{237+6}{15}$$

Add 237 and 6 to get 243.

$$\frac{243}{15}$$

Reduce the fraction \frac{243}{15} to lowest terms by extracting and canceling out 3.

$$\frac{81}{5}$$

Factor

$$\frac{3 ^ {4}}{5} = 16\frac{1}{5} = 16.2$$