Solve (3-7(5-6))(-3(-2)+5(-4))+8(6(3)-2)

$$(3-7(5-6))(-3(-2)+5(-4))+8(6(3)-2)$$

Evaluate

$$-12$$

Solution Steps

Subtract 6 from 5 to get -1.

$$\left(3-7\left(-1\right)\right)\left(-3\left(-2\right)+5\left(-4\right)\right)+8\left(6\times 3-2\right)$$

Multiply 7 and -1 to get -7.

$$\left(3-\left(-7\right)\right)\left(-3\left(-2\right)+5\left(-4\right)\right)+8\left(6\times 3-2\right)$$

The opposite of -7 is 7.

$$\left(3+7\right)\left(-3\left(-2\right)+5\left(-4\right)\right)+8\left(6\times 3-2\right)$$

Add 3 and 7 to get 10.

$$10\left(-3\left(-2\right)+5\left(-4\right)\right)+8\left(6\times 3-2\right)$$

Multiply -3 and -2 to get 6. Multiply 5 and -4 to get -20.

$$10\left(6-20\right)+8\left(6\times 3-2\right)$$

Subtract 20 from 6 to get -14.

$$10\left(-14\right)+8\left(6\times 3-2\right)$$

Multiply 10 and -14 to get -140.

$$-140+8\left(6\times 3-2\right)$$

Multiply 6 and 3 to get 18.

$$-140+8\left(18-2\right)$$

Subtract 2 from 18 to get 16.

$$-140+8\times 16$$

Multiply 8 and 16 to get 128.

$$-140+128$$

Add -140 and 128 to get -12.

$$-12$$

Factor

$$-12$$