Solve (3+4.3)*(((7.1+6.6)-(1.2-.8+4.6)+10-(2.9+4.3)))=

$$(3+4.3) \times (((7.1+6.6)-(1.2-.8+4.6)+10-(2.9+4.3)))=$$

Evaluate

$$83.95$$

Solution Steps

Add 3 and 4.3 to get 7.3.

$$7.3\left(7.1+6.6-\left(1.2-0.8+4.6\right)+10-\left(2.9+4.3\right)\right)$$

Add 7.1 and 6.6 to get 13.7.

$$7.3\left(13.7-\left(1.2-0.8+4.6\right)+10-\left(2.9+4.3\right)\right)$$

Subtract 0.8 from 1.2 to get 0.4.

$$7.3\left(13.7-\left(0.4+4.6\right)+10-\left(2.9+4.3\right)\right)$$

Add 0.4 and 4.6 to get 5.

$$7.3\left(13.7-5+10-\left(2.9+4.3\right)\right)$$

Subtract 5 from 13.7 to get 8.7.

$$7.3\left(8.7+10-\left(2.9+4.3\right)\right)$$

Add 8.7 and 10 to get 18.7.

$$7.3\left(18.7-\left(2.9+4.3\right)\right)$$

Add 2.9 and 4.3 to get 7.2.

$$7.3\left(18.7-7.2\right)$$

Subtract 7.2 from 18.7 to get 11.5.

$$7.3\times 11.5$$

Multiply 7.3 and 11.5 to get 83.95.

$$83.95$$

Factor

$$\frac{23 \cdot 73}{5 \cdot 2 ^ {2}} = 83\frac{19}{20} = 83.95$$