Solve (3*0.18)*xgeq28-15

$$(3 \times 0.18) \times x \geq 28-15$$

Solve for x

$$x\geq \frac{650}{27}$$

Solution Steps

Multiply 3 and 0.18 to get 0.54.

$$0.54x\geq 28-15$$

Subtract 15 from 28 to get 13.

$$0.54x\geq 13$$

Divide both sides by 0.54. Since 0.54 is positive, the inequality direction remains the same.

$$x\geq \frac{13}{0.54}$$

Expand \frac{13}{0.54} by multiplying both numerator and the denominator by 100.

$$x\geq \frac{1300}{54}$$

Reduce the fraction \frac{1300}{54} to lowest terms by extracting and canceling out 2.

$$x\geq \frac{650}{27}$$