Solve (2x-4)(3-6x)=(3x-5)(1-4x)

$$(2x-4)(3-6x)=(3x-5)(1-4x)$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2x-4 by 3-6x and combine like terms.

$$30x-12x^{2}-12=\left(3x-5\right)\left(1-4x\right)$$

Use the distributive property to multiply 3x-5 by 1-4x and combine like terms.

$$30x-12x^{2}-12=23x-12x^{2}-5$$

Subtract 23x from both sides.

$$30x-12x^{2}-12-23x=-12x^{2}-5$$

Combine 30x and -23x to get 7x.

$$7x-12x^{2}-12=-12x^{2}-5$$

Add 12x^{2} to both sides.

$$7x-12x^{2}-12+12x^{2}=-5$$

Combine -12x^{2} and 12x^{2} to get 0.

$$7x-12=-5$$

Add 12 to both sides.

$$7x=-5+12$$

Add -5 and 12 to get 7.

$$7x=7$$

Divide both sides by 7.

$$x=\frac{7}{7}$$

Divide 7 by 7 to get 1.

$$x=1$$