Solve (21+24+28+33+39+42+46+49)div8*30

$$(21+24+28+33+39+42+46+49) \div 8 \times 30$$

Evaluate

$$\frac{2115}{2}=1057.5$$

Solution Steps

Add 21 and 24 to get 45.

$$\frac{45+28+33+39+42+46+49}{8}\times 30$$

Add 45 and 28 to get 73.

$$\frac{73+33+39+42+46+49}{8}\times 30$$

Add 73 and 33 to get 106.

$$\frac{106+39+42+46+49}{8}\times 30$$

Add 106 and 39 to get 145.

$$\frac{145+42+46+49}{8}\times 30$$

Add 145 and 42 to get 187.

$$\frac{187+46+49}{8}\times 30$$

Add 187 and 46 to get 233.

$$\frac{233+49}{8}\times 30$$

Add 233 and 49 to get 282.

$$\frac{282}{8}\times 30$$

Reduce the fraction \frac{282}{8} to lowest terms by extracting and canceling out 2.

$$\frac{141}{4}\times 30$$

Express \frac{141}{4}\times 30 as a single fraction.

$$\frac{141\times 30}{4}$$

Multiply 141 and 30 to get 4230.

$$\frac{4230}{4}$$

Reduce the fraction \frac{4230}{4} to lowest terms by extracting and canceling out 2.

$$\frac{2115}{2}$$

Factor

$$\frac{3 ^ {2} \cdot 5 \cdot 47}{2} = 1057\frac{1}{2} = 1057.5$$