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10\sqrt{3}-2-5\left(\sqrt{3}\right)^{2}+\sqrt{3}
Apply the distributive property by multiplying each term of 2-\sqrt{3} by each term of 5\sqrt{3}-1.
10\sqrt{3}-2-5\times 3+\sqrt{3}
The square of \sqrt{3} is 3.
10\sqrt{3}-2-15+\sqrt{3}
Multiply -5 and 3 to get -15.
10\sqrt{3}-17+\sqrt{3}
Subtract 15 from -2 to get -17.
11\sqrt{3}-17
Combine 10\sqrt{3} and \sqrt{3} to get 11\sqrt{3}.