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8+4\sqrt{3}-4\sqrt{3}-2\left(\sqrt{3}\right)^{2}
Apply the distributive property by multiplying each term of 2-\sqrt{3} by each term of 4+2\sqrt{3}.
8-2\left(\sqrt{3}\right)^{2}
Combine 4\sqrt{3} and -4\sqrt{3} to get 0.
8-2\times 3
The square of \sqrt{3} is 3.
8-6
Multiply -2 and 3 to get -6.
2
Subtract 6 from 8 to get 2.
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