Solve (2+1)(3/4+3/2+1

$$(2+1)( \frac{ 3 }{ 4 } + \frac{ 3 }{ 2 } +1$$

Evaluate

$$\frac{39}{4}=9.75$$

Solution Steps

Add 2 and 1 to get 3.

$$3\left(\frac{3}{4}+\frac{3}{2}+1\right)$$

Least common multiple of 4 and 2 is 4. Convert \frac{3}{4} and \frac{3}{2} to fractions with denominator 4.

$$3\left(\frac{3}{4}+\frac{6}{4}+1\right)$$

Since \frac{3}{4} and \frac{6}{4} have the same denominator, add them by adding their numerators.

$$3\left(\frac{3+6}{4}+1\right)$$

Add 3 and 6 to get 9.

$$3\left(\frac{9}{4}+1\right)$$

Convert 1 to fraction \frac{4}{4}.

$$3\left(\frac{9}{4}+\frac{4}{4}\right)$$

Since \frac{9}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$3\times \frac{9+4}{4}$$

Add 9 and 4 to get 13.

$$3\times \frac{13}{4}$$

Express 3\times \frac{13}{4} as a single fraction.

$$\frac{3\times 13}{4}$$

Multiply 3 and 13 to get 39.

$$\frac{39}{4}$$

Factor

$$\frac{3 \cdot 13}{2 ^ {2}} = 9\frac{3}{4} = 9.75$$