Solve (2*-2+3)(5(-2^2)+3*-2+2

$$(2 \times -2+3)(5(- { 2 }^{ 2 } )+3 \times -2+2$$

Evaluate

$$24$$

Solution Steps

Multiply 2 and -2 to get -4.

$$\left(-4+3\right)\left(5\left(-2^{2}\right)+3\left(-2\right)+2\right)$$

Add -4 and 3 to get -1.

$$-\left(5\left(-2^{2}\right)+3\left(-2\right)+2\right)$$

Calculate 2 to the power of 2 and get 4.

$$-\left(5\left(-4\right)+3\left(-2\right)+2\right)$$

Multiply 5 and -4 to get -20.

$$-\left(-20+3\left(-2\right)+2\right)$$

Multiply 3 and -2 to get -6.

$$-\left(-20-6+2\right)$$

Subtract 6 from -20 to get -26.

$$-\left(-26+2\right)$$

Add -26 and 2 to get -24.

$$-\left(-24\right)$$

Multiply -1 and -24 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$