Solve (14x^2-19x-3)div2x+3

$$(14 { x }^{ 2 } -19x-3) \div 2x+3$$

Evaluate

$$\frac{x\left(2x-3\right)\left(7x+1\right)+6}{2}$$

Short Solution Steps

Express \frac{14x^{2}-19x-3}{2}x as a single fraction.

$$\frac{\left(14x^{2}-19x-3\right)x}{2}+3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2}{2}.

$$\frac{\left(14x^{2}-19x-3\right)x}{2}+\frac{3\times 2}{2}$$

Since \frac{\left(14x^{2}-19x-3\right)x}{2} and \frac{3\times 2}{2} have the same denominator, add them by adding their numerators.

$$\frac{\left(14x^{2}-19x-3\right)x+3\times 2}{2}$$

Do the multiplications in \left(14x^{2}-19x-3\right)x+3\times 2.

$$\frac{14x^{3}-19x^{2}-3x+6}{2}$$

Expand

$$7x^{3}-\frac{19x^{2}}{2}-\frac{3x}{2}+3$$

Short Solution Steps

Express \frac{14x^{2}-19x-3}{2}x as a single fraction.

$$\frac{\left(14x^{2}-19x-3\right)x}{2}+3$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2}{2}.

$$\frac{\left(14x^{2}-19x-3\right)x}{2}+\frac{3\times 2}{2}$$

Since \frac{\left(14x^{2}-19x-3\right)x}{2} and \frac{3\times 2}{2} have the same denominator, add them by adding their numerators.

$$\frac{\left(14x^{2}-19x-3\right)x+3\times 2}{2}$$

Do the multiplications in \left(14x^{2}-19x-3\right)x+3\times 2.

$$\frac{14x^{3}-19x^{2}-3x+6}{2}$$