Solve (1+3+9div2+27div6+81div24+243div120)*{(e)^-3}

$$(1+3+9 \div 2+27 \div 6+81 \div 24+243 \div 120) \times {(e)^{ -3 }}$$

Evaluate

$$\frac{92}{5e^{3}}\approx 0.916082058$$

Solution Steps

Add 1 and 3 to get 4.

$$\left(4+\frac{9}{2}+\frac{27}{6}+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Add 4 and \frac{9}{2} to get \frac{17}{2}.

$$\left(\frac{17}{2}+\frac{27}{6}+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Reduce the fraction \frac{27}{6} to lowest terms by extracting and canceling out 3.

$$\left(\frac{17}{2}+\frac{9}{2}+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Add \frac{17}{2} and \frac{9}{2} to get 13.

$$\left(13+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Reduce the fraction \frac{81}{24} to lowest terms by extracting and canceling out 3.

$$\left(13+\frac{27}{8}+\frac{243}{120}\right)e^{-3}$$

Add 13 and \frac{27}{8} to get \frac{131}{8}.

$$\left(\frac{131}{8}+\frac{243}{120}\right)e^{-3}$$

Reduce the fraction \frac{243}{120} to lowest terms by extracting and canceling out 3.

$$\left(\frac{131}{8}+\frac{81}{40}\right)e^{-3}$$

Add \frac{131}{8} and \frac{81}{40} to get \frac{92}{5}.

$$\frac{92}{5}e^{-3}$$

Expand

$$\frac{92}{5e^{3}}$$

Solution Steps

Add 1 and 3 to get 4.

$$\left(4+\frac{9}{2}+\frac{27}{6}+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Add 4 and \frac{9}{2} to get \frac{17}{2}.

$$\left(\frac{17}{2}+\frac{27}{6}+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Reduce the fraction \frac{27}{6} to lowest terms by extracting and canceling out 3.

$$\left(\frac{17}{2}+\frac{9}{2}+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Add \frac{17}{2} and \frac{9}{2} to get 13.

$$\left(13+\frac{81}{24}+\frac{243}{120}\right)e^{-3}$$

Reduce the fraction \frac{81}{24} to lowest terms by extracting and canceling out 3.

$$\left(13+\frac{27}{8}+\frac{243}{120}\right)e^{-3}$$

Add 13 and \frac{27}{8} to get \frac{131}{8}.

$$\left(\frac{131}{8}+\frac{243}{120}\right)e^{-3}$$

Reduce the fraction \frac{243}{120} to lowest terms by extracting and canceling out 3.

$$\left(\frac{131}{8}+\frac{81}{40}\right)e^{-3}$$

Add \frac{131}{8} and \frac{81}{40} to get \frac{92}{5}.

$$\frac{92}{5}e^{-3}$$