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1-x\leq 0 x-5\leq 0
For the product to be ≥0, 1-x and x-5 have to be both ≤0 or both ≥0. Consider the case when 1-x and x-5 are both ≤0.
x\in \begin{bmatrix}1,5\end{bmatrix}
The solution satisfying both inequalities is x\in \left[1,5\right].
x-5\geq 0 1-x\geq 0
Consider the case when 1-x and x-5 are both ≥0.
x\in \emptyset
This is false for any x.
x\in \begin{bmatrix}1,5\end{bmatrix}
The final solution is the union of the obtained solutions.