Solve (-7+2)-left(3(-7)-1right)^2-7^2+4

$$(-7+2)- { \left(3(-7)-1 \right) }^{ 2 } { -7 }^{ 2 } +4$$

Evaluate

$$-23717$$

Solution Steps

Add -7 and 2 to get -5.

$$-5-\left(3\left(-7\right)-1\right)^{2}\left(-7\right)^{2}+4$$

Multiply 3 and -7 to get -21.

$$-5-\left(-21-1\right)^{2}\left(-7\right)^{2}+4$$

Subtract 1 from -21 to get -22.

$$-5-\left(-22\right)^{2}\left(-7\right)^{2}+4$$

Calculate -22 to the power of 2 and get 484.

$$-5-484\left(-7\right)^{2}+4$$

Calculate -7 to the power of 2 and get 49.

$$-5-484\times 49+4$$

Multiply 484 and 49 to get 23716.

$$-5-23716+4$$

Subtract 23716 from -5 to get -23721.

$$-23721+4$$

Add -23721 and 4 to get -23717.

$$-23717$$

Factor

$$-23717$$