Solve ((((25000*left(13+18right)+250000+500000-350000-750000)div047))div10

$$((((25000 \times \left( 13+18 \right) +250000+500000-350000-750000) \div 047)) \div 10$$

Evaluate

$$\frac{42500}{47}\approx 904.255319149$$

Solution Steps

Express \frac{\frac{25000\left(13+18\right)+250000+500000-350000-750000}{47}}{10} as a single fraction.

$$\frac{25000\left(13+18\right)+250000+500000-350000-750000}{47\times 10}$$

Add 13 and 18 to get 31.

$$\frac{25000\times 31+250000+500000-350000-750000}{47\times 10}$$

Multiply 25000 and 31 to get 775000.

$$\frac{775000+250000+500000-350000-750000}{47\times 10}$$

Add 775000 and 250000 to get 1025000.

$$\frac{1025000+500000-350000-750000}{47\times 10}$$

Add 1025000 and 500000 to get 1525000.

$$\frac{1525000-350000-750000}{47\times 10}$$

Subtract 350000 from 1525000 to get 1175000.

$$\frac{1175000-750000}{47\times 10}$$

Subtract 750000 from 1175000 to get 425000.

$$\frac{425000}{47\times 10}$$

Multiply 47 and 10 to get 470.

$$\frac{425000}{470}$$

Reduce the fraction \frac{425000}{470} to lowest terms by extracting and canceling out 10.

$$\frac{42500}{47}$$

Factor

$$\frac{2 ^ {2} \cdot 5 ^ {4} \cdot 17}{47} = 904\frac{12}{47} = 904.2553191489362$$