Solve for y
y=\left(x+3\right)^{2}+6
Solve for x (complex solution)
x=-\left(\sqrt{y-6}+3\right)
x=\sqrt{y-6}-3
Solve for x
x=-\left(\sqrt{y-6}+3\right)
x=\sqrt{y-6}-3\text{, }y\geq 6
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y-6=x^{2}+6x+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
y=x^{2}+6x+9+6
Add 6 to both sides.
y=x^{2}+6x+15
Add 9 and 6 to get 15.
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