Solve (x-8)^2-x(x+6)=-2

$$( x - 8 ) ^ { 2 } - x ( x + 6 ) = - 2$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-8\right)^{2}.

$$x^{2}-16x+64-x\left(x+6\right)=-2$$

Use the distributive property to multiply x by x+6.

$$x^{2}-16x+64-\left(x^{2}+6x\right)=-2$$

To find the opposite of x^{2}+6x, find the opposite of each term.

$$x^{2}-16x+64-x^{2}-6x=-2$$

Combine x^{2} and -x^{2} to get 0.

$$-16x+64-6x=-2$$

Combine -16x and -6x to get -22x.

$$-22x+64=-2$$

Subtract 64 from both sides.

$$-22x=-2-64$$

Subtract 64 from -2 to get -66.

$$-22x=-66$$

Divide both sides by -22.

$$x=\frac{-66}{-22}$$

Divide -66 by -22 to get 3.

$$x=3$$