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x^{2}+2x-35=4
Use the distributive property to multiply x-5 by x+7 and combine like terms.
x^{2}+2x-35-4=0
Subtract 4 from both sides.
x^{2}+2x-39=0
Subtract 4 from -35 to get -39.
x=\frac{-2±\sqrt{2^{2}-4\left(-39\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 2 for b, and -39 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2±\sqrt{4-4\left(-39\right)}}{2}
Square 2.
x=\frac{-2±\sqrt{4+156}}{2}
Multiply -4 times -39.
x=\frac{-2±\sqrt{160}}{2}
Add 4 to 156.
x=\frac{-2±4\sqrt{10}}{2}
Take the square root of 160.
x=\frac{4\sqrt{10}-2}{2}
Now solve the equation x=\frac{-2±4\sqrt{10}}{2} when ± is plus. Add -2 to 4\sqrt{10}.
x=2\sqrt{10}-1
Divide -2+4\sqrt{10} by 2.
x=\frac{-4\sqrt{10}-2}{2}
Now solve the equation x=\frac{-2±4\sqrt{10}}{2} when ± is minus. Subtract 4\sqrt{10} from -2.
x=-2\sqrt{10}-1
Divide -2-4\sqrt{10} by 2.
x=2\sqrt{10}-1 x=-2\sqrt{10}-1
The equation is now solved.
x^{2}+2x-35=4
Use the distributive property to multiply x-5 by x+7 and combine like terms.
x^{2}+2x=4+35
Add 35 to both sides.
x^{2}+2x=39
Add 4 and 35 to get 39.
x^{2}+2x+1^{2}=39+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=39+1
Square 1.
x^{2}+2x+1=40
Add 39 to 1.
\left(x+1\right)^{2}=40
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{40}
Take the square root of both sides of the equation.
x+1=2\sqrt{10} x+1=-2\sqrt{10}
Simplify.
x=2\sqrt{10}-1 x=-2\sqrt{10}-1
Subtract 1 from both sides of the equation.