Solve for x
x=-10
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x^{2}-16-6x=\left(x-2\right)^{2}
Consider \left(x-4\right)\left(x+4\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 4.
x^{2}-16-6x=x^{2}-4x+4
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-16-6x-x^{2}=-4x+4
Subtract x^{2} from both sides.
-16-6x=-4x+4
Combine x^{2} and -x^{2} to get 0.
-16-6x+4x=4
Add 4x to both sides.
-16-2x=4
Combine -6x and 4x to get -2x.
-2x=4+16
Add 16 to both sides.
-2x=20
Add 4 and 16 to get 20.
x=\frac{20}{-2}
Divide both sides by -2.
x=-10
Divide 20 by -2 to get -10.
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