Solve (x-4)^2=15

$$( x - 4 ) ^ { 2 } = 15$$

Solve for x

$$x=\sqrt{15}+4\approx 7.872983346$$

$$x=4-\sqrt{15}\approx 0.127016654$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x-4=\sqrt{15} x-4=-\sqrt{15}$$

Add 4 to both sides of the equation.

$$x-4-\left(-4\right)=\sqrt{15}-\left(-4\right) x-4-\left(-4\right)=-\sqrt{15}-\left(-4\right)$$

Subtracting -4 from itself leaves 0.

$$x=\sqrt{15}-\left(-4\right) x=-\sqrt{15}-\left(-4\right)$$

Subtract -4 from \sqrt{15}.

$$x=\sqrt{15}+4$$

Subtract -4 from -\sqrt{15}.

$$x=4-\sqrt{15}$$

The equation is now solved.

$$x=\sqrt{15}+4 x=4-\sqrt{15}$$