Solve (x-3)(x-2)+x(x-3)/2=(x-2)^2

$$( x - 3 ) ( x - 2 ) + \frac { x ( x - 3 ) } { 2 } = ( x - 2 ) ^ { 2 }$$

Solve for x

$$x=1$$

$$x=4$$

Steps Using Factoring

Multiply both sides of the equation by 2.

$$2\left(x-3\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2 by x-3.

$$\left(2x-6\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2x-6 by x-2 and combine like terms.

$$2x^{2}-10x+12+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply x by x-3.

$$2x^{2}-10x+12+x^{2}-3x=2\left(x-2\right)^{2}$$

Combine 2x^{2} and x^{2} to get 3x^{2}.

$$3x^{2}-10x+12-3x=2\left(x-2\right)^{2}$$

Combine -10x and -3x to get -13x.

$$3x^{2}-13x+12=2\left(x-2\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.

$$3x^{2}-13x+12=2\left(x^{2}-4x+4\right)$$

Use the distributive property to multiply 2 by x^{2}-4x+4.

$$3x^{2}-13x+12=2x^{2}-8x+8$$

Subtract 2x^{2} from both sides.

$$3x^{2}-13x+12-2x^{2}=-8x+8$$

Combine 3x^{2} and -2x^{2} to get x^{2}.

$$x^{2}-13x+12=-8x+8$$

Add 8x to both sides.

$$x^{2}-13x+12+8x=8$$

Combine -13x and 8x to get -5x.

$$x^{2}-5x+12=8$$

Subtract 8 from both sides.

$$x^{2}-5x+12-8=0$$

Subtract 8 from 12 to get 4.

$$x^{2}-5x+4=0$$

To solve the equation, factor x^{2}-5x+4 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.

$$a+b=-5 ab=4$$

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 4.

$$-1,-4 -2,-2$$

Calculate the sum for each pair.

$$-1-4=-5 -2-2=-4$$

The solution is the pair that gives sum -5.

$$a=-4 b=-1$$

Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.

$$\left(x-4\right)\left(x-1\right)$$

To find equation solutions, solve x-4=0 and x-1=0.

$$x=4 x=1$$

Steps Using Factoring By Grouping

Multiply both sides of the equation by 2.

$$2\left(x-3\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2 by x-3.

$$\left(2x-6\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2x-6 by x-2 and combine like terms.

$$2x^{2}-10x+12+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply x by x-3.

$$2x^{2}-10x+12+x^{2}-3x=2\left(x-2\right)^{2}$$

Combine 2x^{2} and x^{2} to get 3x^{2}.

$$3x^{2}-10x+12-3x=2\left(x-2\right)^{2}$$

Combine -10x and -3x to get -13x.

$$3x^{2}-13x+12=2\left(x-2\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.

$$3x^{2}-13x+12=2\left(x^{2}-4x+4\right)$$

Use the distributive property to multiply 2 by x^{2}-4x+4.

$$3x^{2}-13x+12=2x^{2}-8x+8$$

Subtract 2x^{2} from both sides.

$$3x^{2}-13x+12-2x^{2}=-8x+8$$

Combine 3x^{2} and -2x^{2} to get x^{2}.

$$x^{2}-13x+12=-8x+8$$

Add 8x to both sides.

$$x^{2}-13x+12+8x=8$$

Combine -13x and 8x to get -5x.

$$x^{2}-5x+12=8$$

Subtract 8 from both sides.

$$x^{2}-5x+12-8=0$$

Subtract 8 from 12 to get 4.

$$x^{2}-5x+4=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+4. To find a and b, set up a system to be solved.

$$a+b=-5 ab=1\times 4=4$$

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 4.

$$-1,-4 -2,-2$$

Calculate the sum for each pair.

$$-1-4=-5 -2-2=-4$$

The solution is the pair that gives sum -5.

$$a=-4 b=-1$$

Rewrite x^{2}-5x+4 as \left(x^{2}-4x\right)+\left(-x+4\right).

$$\left(x^{2}-4x\right)+\left(-x+4\right)$$

Factor out x in the first and -1 in the second group.

$$x\left(x-4\right)-\left(x-4\right)$$

Factor out common term x-4 by using distributive property.

$$\left(x-4\right)\left(x-1\right)$$

To find equation solutions, solve x-4=0 and x-1=0.

$$x=4 x=1$$

Steps Using the Quadratic Formula

Multiply both sides of the equation by 2.

$$2\left(x-3\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2 by x-3.

$$\left(2x-6\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2x-6 by x-2 and combine like terms.

$$2x^{2}-10x+12+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply x by x-3.

$$2x^{2}-10x+12+x^{2}-3x=2\left(x-2\right)^{2}$$

Combine 2x^{2} and x^{2} to get 3x^{2}.

$$3x^{2}-10x+12-3x=2\left(x-2\right)^{2}$$

Combine -10x and -3x to get -13x.

$$3x^{2}-13x+12=2\left(x-2\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.

$$3x^{2}-13x+12=2\left(x^{2}-4x+4\right)$$

Use the distributive property to multiply 2 by x^{2}-4x+4.

$$3x^{2}-13x+12=2x^{2}-8x+8$$

Subtract 2x^{2} from both sides.

$$3x^{2}-13x+12-2x^{2}=-8x+8$$

Combine 3x^{2} and -2x^{2} to get x^{2}.

$$x^{2}-13x+12=-8x+8$$

Add 8x to both sides.

$$x^{2}-13x+12+8x=8$$

Combine -13x and 8x to get -5x.

$$x^{2}-5x+12=8$$

Subtract 8 from both sides.

$$x^{2}-5x+12-8=0$$

Subtract 8 from 12 to get 4.

$$x^{2}-5x+4=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -5 for b, and 4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}-4\times 4}}{2}$$

Square -5.

$$x=\frac{-\left(-5\right)±\sqrt{25-4\times 4}}{2}$$

Multiply -4 times 4.

$$x=\frac{-\left(-5\right)±\sqrt{25-16}}{2}$$

Add 25 to -16.

$$x=\frac{-\left(-5\right)±\sqrt{9}}{2}$$

Take the square root of 9.

$$x=\frac{-\left(-5\right)±3}{2}$$

The opposite of -5 is 5.

$$x=\frac{5±3}{2}$$

Now solve the equation x=\frac{5±3}{2} when ± is plus. Add 5 to 3.

$$x=\frac{8}{2}$$

Divide 8 by 2.

$$x=4$$

Now solve the equation x=\frac{5±3}{2} when ± is minus. Subtract 3 from 5.

$$x=\frac{2}{2}$$

Divide 2 by 2.

$$x=1$$

The equation is now solved.

$$x=4 x=1$$

Steps for Completing the Square

Multiply both sides of the equation by 2.

$$2\left(x-3\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2 by x-3.

$$\left(2x-6\right)\left(x-2\right)+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply 2x-6 by x-2 and combine like terms.

$$2x^{2}-10x+12+x\left(x-3\right)=2\left(x-2\right)^{2}$$

Use the distributive property to multiply x by x-3.

$$2x^{2}-10x+12+x^{2}-3x=2\left(x-2\right)^{2}$$

Combine 2x^{2} and x^{2} to get 3x^{2}.

$$3x^{2}-10x+12-3x=2\left(x-2\right)^{2}$$

Combine -10x and -3x to get -13x.

$$3x^{2}-13x+12=2\left(x-2\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.

$$3x^{2}-13x+12=2\left(x^{2}-4x+4\right)$$

Use the distributive property to multiply 2 by x^{2}-4x+4.

$$3x^{2}-13x+12=2x^{2}-8x+8$$

Subtract 2x^{2} from both sides.

$$3x^{2}-13x+12-2x^{2}=-8x+8$$

Combine 3x^{2} and -2x^{2} to get x^{2}.

$$x^{2}-13x+12=-8x+8$$

Add 8x to both sides.

$$x^{2}-13x+12+8x=8$$

Combine -13x and 8x to get -5x.

$$x^{2}-5x+12=8$$

Subtract 12 from both sides.

$$x^{2}-5x=8-12$$

Subtract 12 from 8 to get -4.

$$x^{2}-5x=-4$$

Divide -5, the coefficient of the x term, by 2 to get -\frac{5}{2}. Then add the square of -\frac{5}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-5x+\left(-\frac{5}{2}\right)^{2}=-4+\left(-\frac{5}{2}\right)^{2}$$

Square -\frac{5}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-5x+\frac{25}{4}=-4+\frac{25}{4}$$

Add -4 to \frac{25}{4}.

$$x^{2}-5x+\frac{25}{4}=\frac{9}{4}$$

Factor x^{2}-5x+\frac{25}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{5}{2}\right)^{2}=\frac{9}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{5}{2}\right)^{2}}=\sqrt{\frac{9}{4}}$$

Simplify.

$$x-\frac{5}{2}=\frac{3}{2} x-\frac{5}{2}=-\frac{3}{2}$$

Add \frac{5}{2} to both sides of the equation.

$$x=4 x=1$$