Solve (x-3)^2-10=0

$$( x - 3 ) ^ { 2 } - 10 = 0$$

Solve for x

$$x=\sqrt{10}+3\approx 6.16227766$$

$$x=3-\sqrt{10}\approx -0.16227766$$

Steps by Finding Square Root

Add 10 to both sides of the equation.

$$\left(x-3\right)^{2}-10+10=10$$

Subtracting 10 from itself leaves 0.

$$\left(x-3\right)^{2}=10$$

Take the square root of both sides of the equation.

$$x-3=\sqrt{10} x-3=-\sqrt{10}$$

Add 3 to both sides of the equation.

$$x-3-\left(-3\right)=\sqrt{10}-\left(-3\right) x-3-\left(-3\right)=-\sqrt{10}-\left(-3\right)$$

Subtracting -3 from itself leaves 0.

$$x=\sqrt{10}-\left(-3\right) x=-\sqrt{10}-\left(-3\right)$$

Subtract -3 from \sqrt{10}.

$$x=\sqrt{10}+3$$

Subtract -3 from -\sqrt{10}.

$$x=3-\sqrt{10}$$

The equation is now solved.

$$x=\sqrt{10}+3 x=3-\sqrt{10}$$