Solve (x-2)^2-(x+2)^2+3=0

$$( x - 2 ) ^ { 2 } - ( x + 2 ) ^ { 2 } + 3 = 0$$

Solve for x

$$x=\frac{3}{8}=0.375$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.

$$x^{2}-4x+4-\left(x+2\right)^{2}+3=0$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.

$$x^{2}-4x+4-\left(x^{2}+4x+4\right)+3=0$$

To find the opposite of x^{2}+4x+4, find the opposite of each term.

$$x^{2}-4x+4-x^{2}-4x-4+3=0$$

Combine x^{2} and -x^{2} to get 0.

$$-4x+4-4x-4+3=0$$

Combine -4x and -4x to get -8x.

$$-8x+4-4+3=0$$

Subtract 4 from 4 to get 0.

$$-8x+3=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$-8x=-3$$

Divide both sides by -8.

$$x=\frac{-3}{-8}$$

Fraction \frac{-3}{-8} can be simplified to \frac{3}{8} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{3}{8}$$