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x^{2}-2x+1-\frac{7}{3}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
x^{2}-2x-\frac{4}{3}
Subtract \frac{7}{3} from 1 to get -\frac{4}{3}.
x^{2}-2x+1-\frac{7}{3}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
x^{2}-2x-\frac{4}{3}
Subtract \frac{7}{3} from 1 to get -\frac{4}{3}.