Solve (x-0)^2+(4+3)^2=4

$$( x - 0 ) ^ { 2 } + ( 4 + 3 ) ^ { 2 } = 4$$

Solve for x (complex solution)

$$x=-3\sqrt{5}i\approx -0-6.708203932i$$

$$x=3\sqrt{5}i\approx 6.708203932i$$

Steps by Finding Square Root

Add 4 and 3 to get 7.

$$\left(x-0\right)^{2}+7^{2}=4$$

Calculate 7 to the power of 2 and get 49.

$$\left(x-0\right)^{2}+49=4$$

Subtract 49 from both sides.

$$\left(x-0\right)^{2}=4-49$$

Subtract 49 from 4 to get -45.

$$\left(x-0\right)^{2}=-45$$

Reorder the terms.

$$x^{2}=-45$$

The equation is now solved.

$$x=3\sqrt{5}i x=-3\sqrt{5}i$$

Steps Using the Quadratic Formula

Add 4 and 3 to get 7.

$$\left(x-0\right)^{2}+7^{2}=4$$

Calculate 7 to the power of 2 and get 49.

$$\left(x-0\right)^{2}+49=4$$

Subtract 4 from both sides.

$$\left(x-0\right)^{2}+49-4=0$$

Subtract 4 from 49 to get 45.

$$\left(x-0\right)^{2}+45=0$$

Reorder the terms.

$$x^{2}+45=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 45 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 45}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 45}}{2}$$

Multiply -4 times 45.

$$x=\frac{0±\sqrt{-180}}{2}$$

Take the square root of -180.

$$x=\frac{0±6\sqrt{5}i}{2}$$

Now solve the equation x=\frac{0±6\sqrt{5}i}{2} when ± is plus.

$$x=3\sqrt{5}i$$

Now solve the equation x=\frac{0±6\sqrt{5}i}{2} when ± is minus.

$$x=-3\sqrt{5}i$$

The equation is now solved.

$$x=3\sqrt{5}i x=-3\sqrt{5}i$$