Solve (x)=x^3-2x^2+4x-5text{makanilaidari}f^prime(2)

$$( x ) = x ^ { 3 } - 2 x ^ { 2 } + 4 x - 5 \text { maka nilai dari } f ^ { \prime } ( 2 )$$

Solve for d

$$d\in \mathrm{C}$$

$$x=-\sqrt{2}i+1\text{ or }x=1+\sqrt{2}i\text{ or }x=0$$

Steps for Solving Linear Equation

Multiply a and a to get a^{2}.

$$x=x^{3}-2x^{2}+4x-5ma^{2}knilaidari\frac{\mathrm{d}}{\mathrm{d}x}(f)\times 2$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$x=x^{3}-2x^{2}+4x-5ma^{3}knilidari\frac{\mathrm{d}}{\mathrm{d}x}(f)\times 2$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$x=x^{3}-2x^{2}+4x-5ma^{4}knilidri\frac{\mathrm{d}}{\mathrm{d}x}(f)\times 2$$

Multiply 5 and i to get 5i.

$$x=x^{3}-2x^{2}+4x-5ima^{4}knlidri\frac{\mathrm{d}}{\mathrm{d}x}(f)\times 2$$

Multiply 5i and i to get -5.

$$x=x^{3}-2x^{2}+4x-\left(-5ma^{4}knldri\frac{\mathrm{d}}{\mathrm{d}x}(f)\times 2\right)$$

Multiply -5 and i to get -5i.

$$x=x^{3}-2x^{2}+4x-\left(-5ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)\times 2\right)$$

Multiply -5i and 2 to get -10i.

$$x=x^{3}-2x^{2}+4x-\left(-10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)\right)$$

Swap sides so that all variable terms are on the left hand side.

$$x^{3}-2x^{2}+4x-\left(-10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)\right)=x$$

Multiply -1 and -10i to get 10i.

$$x^{3}-2x^{2}+4x+10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)=x$$

Subtract x^{3} from both sides.

$$-2x^{2}+4x+10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)=x-x^{3}$$

Add 2x^{2} to both sides.

$$4x+10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)=x-x^{3}+2x^{2}$$

Subtract 4x from both sides.

$$10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)=x-x^{3}+2x^{2}-4x$$

Combine x and -4x to get -3x.

$$10ima^{4}knldr\frac{\mathrm{d}}{\mathrm{d}x}(f)=-3x-x^{3}+2x^{2}$$

The equation is in standard form.

$$0=-x^{3}+2x^{2}-3x$$

This is false for any d.

$$d\in$$

Solve for a

$$a\in \mathrm{C}$$

$$x=-\sqrt{2}i+1\text{ or }x=1+\sqrt{2}i\text{ or }x=0$$