Factor
\left(x-7\right)\left(x^{2}+7x+49\right)
Evaluate
x^{3}-343
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\left(x-7\right)\left(x^{2}+7x+49\right)
Rewrite x^{3}-343 as x^{3}-7^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial x^{2}+7x+49 is not factored since it does not have any rational roots.
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