Solve (x+z^2)=2x+7

$$( x + z ^ { 2 } ) = 2 x + 7$$

Solve for x

$$x=z^{2}-7$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$x+z^{2}-2x=7$$

Combine x and -2x to get -x.

$$-x+z^{2}=7$$

Subtract z^{2} from both sides.

$$-x=7-z^{2}$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{7-z^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{7-z^{2}}{-1}$$

Divide 7-z^{2} by -1.

$$x=z^{2}-7$$

Solve for z (complex solution)

$$z=-\sqrt{x+7}$$

$$z=\sqrt{x+7}$$

Solve for z

$$z=\sqrt{x+7}$$

$$z=-\sqrt{x+7}\text{, }x\geq -7$$