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Solve for a (complex solution)
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Solve for x (complex solution)
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Solve for a
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Solve for x
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x^{2}+2xa+a^{2}=x^{2}+2ax+a^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+a\right)^{2}.
x^{2}+2xa+a^{2}-2ax=x^{2}+a^{2}
Subtract 2ax from both sides.
x^{2}+a^{2}=x^{2}+a^{2}
Combine 2xa and -2ax to get 0.
x^{2}+a^{2}-a^{2}=x^{2}
Subtract a^{2} from both sides.
x^{2}=x^{2}
Combine a^{2} and -a^{2} to get 0.
\text{true}
Reorder the terms.
a\in \mathrm{C}
This is true for any a.
x^{2}+2xa+a^{2}=x^{2}+2ax+a^{2}
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(x+a\right)^{2}.
x^{2}+2xa+a^{2}-x^{2}=2ax+a^{2}
Subtract x^{2} from both sides.
2xa+a^{2}=2ax+a^{2}
Combine x^{2} and -x^{2} to get 0.
2xa+a^{2}-2ax=a^{2}
Subtract 2ax from both sides.
a^{2}=a^{2}
Combine 2xa and -2ax to get 0.
\text{true}
Reorder the terms.
x\in \mathrm{C}
This is true for any x.
x^{2}+2xa+a^{2}=x^{2}+2ax+a^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+a\right)^{2}.
x^{2}+2xa+a^{2}-2ax=x^{2}+a^{2}
Subtract 2ax from both sides.
x^{2}+a^{2}=x^{2}+a^{2}
Combine 2xa and -2ax to get 0.
x^{2}+a^{2}-a^{2}=x^{2}
Subtract a^{2} from both sides.
x^{2}=x^{2}
Combine a^{2} and -a^{2} to get 0.
\text{true}
Reorder the terms.
a\in \mathrm{R}
This is true for any a.
x^{2}+2xa+a^{2}=x^{2}+2ax+a^{2}
Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(x+a\right)^{2}.
x^{2}+2xa+a^{2}-x^{2}=2ax+a^{2}
Subtract x^{2} from both sides.
2xa+a^{2}=2ax+a^{2}
Combine x^{2} and -x^{2} to get 0.
2xa+a^{2}-2ax=a^{2}
Subtract 2ax from both sides.
a^{2}=a^{2}
Combine 2xa and -2ax to get 0.
\text{true}
Reorder the terms.
x\in \mathrm{R}
This is true for any x.