Solve (x+9)^2+27=0

$$( x + 9 ) ^ { 2 } + 27 = 0$$

Solve for x (complex solution)

$$x=-3\sqrt{3}i-9\approx -9-5.196152423i$$

$$x=-9+3\sqrt{3}i\approx -9+5.196152423i$$

Steps by Finding Square Root

Subtracting 27 from itself leaves 0.

$$\left(x+9\right)^{2}=-27$$

Take the square root of both sides of the equation.

$$x+9=3\sqrt{3}i x+9=-3\sqrt{3}i$$

Subtract 9 from both sides of the equation.

$$x+9-9=3\sqrt{3}i-9 x+9-9=-3\sqrt{3}i-9$$

Subtracting 9 from itself leaves 0.

$$x=3\sqrt{3}i-9 x=-3\sqrt{3}i-9$$

Subtract 9 from 3i\sqrt{3}.

$$x=-9+3\sqrt{3}i$$

Subtract 9 from -3i\sqrt{3}.

$$x=-3\sqrt{3}i-9$$

The equation is now solved.

$$x=-9+3\sqrt{3}i x=-3\sqrt{3}i-9$$