Solve (x+7):x=(7+2)*y

$$( x + 7 ) : x = ( 7 + 2 ) \cdot y$$

Solve for x

$$x=-\frac{7}{1-9y}$$

$$y\neq \frac{1}{9}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$x+7=\left(7+2\right)yx$$

Add 7 and 2 to get 9.

$$x+7=9yx$$

Subtract 9yx from both sides.

$$x+7-9yx=0$$

Subtract 7 from both sides. Anything subtracted from zero gives its negation.

$$x-9yx=-7$$

Combine all terms containing x.

$$\left(1-9y\right)x=-7$$

Divide both sides by 1-9y.

$$\frac{\left(1-9y\right)x}{1-9y}=-\frac{7}{1-9y}$$

Dividing by 1-9y undoes the multiplication by 1-9y.

$$x=-\frac{7}{1-9y}$$

Variable x cannot be equal to 0.

$$x=-\frac{7}{1-9y}\text{, }x\neq 0$$

Solve for y

$$y=\frac{1}{9}+\frac{7}{9x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x.

$$x+7=\left(7+2\right)yx$$

Add 7 and 2 to get 9.

$$x+7=9yx$$

Swap sides so that all variable terms are on the left hand side.

$$9yx=x+7$$

The equation is in standard form.

$$9xy=x+7$$

Divide both sides by 9x.

$$\frac{9xy}{9x}=\frac{x+7}{9x}$$

Dividing by 9x undoes the multiplication by 9x.

$$y=\frac{x+7}{9x}$$

Divide x+7 by 9x.

$$y=\frac{1}{9}+\frac{7}{9x}$$