Solve (x+7)+(3-4x)+(2x-9)

$$( x + 7 ) + ( 3 - 4 x ) + ( 2 x - 9 )$$

Evaluate

$$1-x$$

Solution Steps

Add 7 and 3 to get 10.

$$x+10-4x+2x-9$$

Combine x and -4x to get -3x.

$$-3x+10+2x-9$$

Combine -3x and 2x to get -x.

$$-x+10-9$$

Subtract 9 from 10 to get 1.

$$-x+1$$

Differentiate w.r.t. x

$$-1$$

Steps Using Derivative Rule for Sum

Add 7 and 3 to get 10.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+10-4x+2x-9)$$

Combine x and -4x to get -3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3x+10+2x-9)$$

Combine -3x and 2x to get -x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x+10-9)$$

Subtract 9 from 10 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-x+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-x^{1-1}$$

Subtract 1 from 1.

$$-x^{0}$$

For any term t except 0, t^{0}=1.

$$-1$$