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x^{2}-36-3x=x^{2}-25
Consider \left(x+6\right)\left(x-6\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 6.
x^{2}-36-3x-x^{2}=-25
Subtract x^{2} from both sides.
-36-3x=-25
Combine x^{2} and -x^{2} to get 0.
-3x=-25+36
Add 36 to both sides.
-3x=11
Add -25 and 36 to get 11.
x=\frac{11}{-3}
Divide both sides by -3.
x=-\frac{11}{3}
Fraction \frac{11}{-3} can be rewritten as -\frac{11}{3} by extracting the negative sign.