Solve for x
x=2
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x^{2}+12x+36=\left(x+14\right)\left(x+2\right)
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+6\right)^{2}.
x^{2}+12x+36=x^{2}+16x+28
Use the distributive property to multiply x+14 by x+2 and combine like terms.
x^{2}+12x+36-x^{2}=16x+28
Subtract x^{2} from both sides.
12x+36=16x+28
Combine x^{2} and -x^{2} to get 0.
12x+36-16x=28
Subtract 16x from both sides.
-4x+36=28
Combine 12x and -16x to get -4x.
-4x=28-36
Subtract 36 from both sides.
-4x=-8
Subtract 36 from 28 to get -8.
x=\frac{-8}{-4}
Divide both sides by -4.
x=2
Divide -8 by -4 to get 2.
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