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x^{2}+6x+9=5^{2}+x^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x+9=25+x^{2}
Calculate 5 to the power of 2 and get 25.
x^{2}+6x+9-x^{2}=25
Subtract x^{2} from both sides.
6x+9=25
Combine x^{2} and -x^{2} to get 0.
6x=25-9
Subtract 9 from both sides.
6x=16
Subtract 9 from 25 to get 16.
x=\frac{16}{6}
Divide both sides by 6.
x=\frac{8}{3}
Reduce the fraction \frac{16}{6} to lowest terms by extracting and canceling out 2.