Solve (x+3)^2+2=-10

$$( x + 3 ) ^ { 2 } + 2 = - 10$$

Solve for x (complex solution)

$$x=-2\sqrt{3}i-3\approx -3-3.464101615i$$

$$x=-3+2\sqrt{3}i\approx -3+3.464101615i$$

Steps by Finding Square Root

Subtracting 2 from itself leaves 0.

$$\left(x+3\right)^{2}=-10-2$$

Subtract 2 from -10.

$$\left(x+3\right)^{2}=-12$$

Take the square root of both sides of the equation.

$$x+3=2\sqrt{3}i x+3=-2\sqrt{3}i$$

Subtract 3 from both sides of the equation.

$$x+3-3=2\sqrt{3}i-3 x+3-3=-2\sqrt{3}i-3$$

Subtracting 3 from itself leaves 0.

$$x=2\sqrt{3}i-3 x=-2\sqrt{3}i-3$$

Subtract 3 from 2i\sqrt{3}.

$$x=-3+2\sqrt{3}i$$

Subtract 3 from -2i\sqrt{3}.

$$x=-2\sqrt{3}i-3$$

The equation is now solved.

$$x=-3+2\sqrt{3}i x=-2\sqrt{3}i-3$$