Solve (x+2)(x-1)=x+3

$$( x + 2 ) ( x - 1 ) = x + 3$$

Solve for x

$$x=\sqrt{5}\approx 2.236067977$$

$$x=-\sqrt{5}\approx -2.236067977$$

Steps by Finding Square Root

Use the distributive property to multiply x+2 by x-1 and combine like terms.

$$x^{2}+x-2=x+3$$

Subtract x from both sides.

$$x^{2}+x-2-x=3$$

Combine x and -x to get 0.

$$x^{2}-2=3$$

Add 2 to both sides.

$$x^{2}=3+2$$

Add 3 and 2 to get 5.

$$x^{2}=5$$

Take the square root of both sides of the equation.

$$x=\sqrt{5} x=-\sqrt{5}$$

Steps Using the Quadratic Formula

Use the distributive property to multiply x+2 by x-1 and combine like terms.

$$x^{2}+x-2=x+3$$

Subtract x from both sides.

$$x^{2}+x-2-x=3$$

Combine x and -x to get 0.

$$x^{2}-2=3$$

Subtract 3 from both sides.

$$x^{2}-2-3=0$$

Subtract 3 from -2 to get -5.

$$x^{2}-5=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-5\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-5\right)}}{2}$$

Multiply -4 times -5.

$$x=\frac{0±\sqrt{20}}{2}$$

Take the square root of 20.

$$x=\frac{0±2\sqrt{5}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{5}}{2} when ± is plus.

$$x=\sqrt{5}$$

Now solve the equation x=\frac{0±2\sqrt{5}}{2} when ± is minus.

$$x=-\sqrt{5}$$

The equation is now solved.

$$x=\sqrt{5} x=-\sqrt{5}$$