Solve for x
x=13
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x^{2}+4x+4-x^{2}=56
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
4x+4=56
Combine x^{2} and -x^{2} to get 0.
4x=56-4
Subtract 4 from both sides.
4x=52
Subtract 4 from 56 to get 52.
x=\frac{52}{4}
Divide both sides by 4.
x=13
Divide 52 by 4 to get 13.
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