Solve (x+2)+a=3/4x=

$$( x + 2 ) + a = \frac { 3 } { 4 } x =$$

Solve for a

$$a=-\frac{x}{4}-2$$

Solution Steps

Subtract x from both sides.

$$2+a=\frac{3}{4}x-x$$

Combine \frac{3}{4}x and -x to get -\frac{1}{4}x.

$$2+a=-\frac{1}{4}x$$

Subtract 2 from both sides.

$$a=-\frac{1}{4}x-2$$

Solve for x

$$x=-4a-8$$

Steps for Solving Linear Equation

Subtract \frac{3}{4}x from both sides.

$$x+2+a-\frac{3}{4}x=0$$

Combine x and -\frac{3}{4}x to get \frac{1}{4}x.

$$\frac{1}{4}x+2+a=0$$

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$\frac{1}{4}x+a=-2$$

Subtract a from both sides.

$$\frac{1}{4}x=-2-a$$

The equation is in standard form.

$$\frac{1}{4}x=-a-2$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}x}{\frac{1}{4}}=\frac{-a-2}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$x=\frac{-a-2}{\frac{1}{4}}$$

Divide -2-a by \frac{1}{4} by multiplying -2-a by the reciprocal of \frac{1}{4}.

$$x=-4a-8$$