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Solve for x (complex solution)
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\left(x-2\right)^{2}=\left(x-2\right)^{2}
Subtract 3 from 1 to get -2.
x^{2}-4x+4=\left(x-2\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-4x+4=x^{2}-4x+4
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-4x+4-x^{2}=-4x+4
Subtract x^{2} from both sides.
-4x+4=-4x+4
Combine x^{2} and -x^{2} to get 0.
-4x+4+4x=4
Add 4x to both sides.
4=4
Combine -4x and 4x to get 0.
\text{true}
Compare 4 and 4.
x\in \mathrm{C}
This is true for any x.
\left(x-2\right)^{2}=\left(x-2\right)^{2}
Subtract 3 from 1 to get -2.
x^{2}-4x+4=\left(x-2\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-4x+4=x^{2}-4x+4
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-4x+4-x^{2}=-4x+4
Subtract x^{2} from both sides.
-4x+4=-4x+4
Combine x^{2} and -x^{2} to get 0.
-4x+4+4x=4
Add 4x to both sides.
4=4
Combine -4x and 4x to get 0.
\text{true}
Compare 4 and 4.
x\in \mathrm{R}
This is true for any x.