Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

x^{2}+3x+2=9
Use the distributive property to multiply x+1 by x+2 and combine like terms.
x^{2}+3x+2-9=0
Subtract 9 from both sides.
x^{2}+3x-7=0
Subtract 9 from 2 to get -7.
x=\frac{-3±\sqrt{3^{2}-4\left(-7\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 3 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-3±\sqrt{9-4\left(-7\right)}}{2}
Square 3.
x=\frac{-3±\sqrt{9+28}}{2}
Multiply -4 times -7.
x=\frac{-3±\sqrt{37}}{2}
Add 9 to 28.
x=\frac{\sqrt{37}-3}{2}
Now solve the equation x=\frac{-3±\sqrt{37}}{2} when ± is plus. Add -3 to \sqrt{37}.
x=\frac{-\sqrt{37}-3}{2}
Now solve the equation x=\frac{-3±\sqrt{37}}{2} when ± is minus. Subtract \sqrt{37} from -3.
x=\frac{\sqrt{37}-3}{2} x=\frac{-\sqrt{37}-3}{2}
The equation is now solved.
x^{2}+3x+2=9
Use the distributive property to multiply x+1 by x+2 and combine like terms.
x^{2}+3x=9-2
Subtract 2 from both sides.
x^{2}+3x=7
Subtract 2 from 9 to get 7.
x^{2}+3x+\left(\frac{3}{2}\right)^{2}=7+\left(\frac{3}{2}\right)^{2}
Divide 3, the coefficient of the x term, by 2 to get \frac{3}{2}. Then add the square of \frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+3x+\frac{9}{4}=7+\frac{9}{4}
Square \frac{3}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}+3x+\frac{9}{4}=\frac{37}{4}
Add 7 to \frac{9}{4}.
\left(x+\frac{3}{2}\right)^{2}=\frac{37}{4}
Factor x^{2}+3x+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{3}{2}\right)^{2}}=\sqrt{\frac{37}{4}}
Take the square root of both sides of the equation.
x+\frac{3}{2}=\frac{\sqrt{37}}{2} x+\frac{3}{2}=-\frac{\sqrt{37}}{2}
Simplify.
x=\frac{\sqrt{37}-3}{2} x=\frac{-\sqrt{37}-3}{2}
Subtract \frac{3}{2} from both sides of the equation.