Solve (x+1)^2=x^2+5

$$( x + 1 ) ^ { 2 } = x ^ { 2 } + 5$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.

$$x^{2}+2x+1=x^{2}+5$$

Subtract x^{2} from both sides.

$$x^{2}+2x+1-x^{2}=5$$

Combine x^{2} and -x^{2} to get 0.

$$2x+1=5$$

Subtract 1 from both sides.

$$2x=5-1$$

Subtract 1 from 5 to get 4.

$$2x=4$$

Divide both sides by 2.

$$x=\frac{4}{2}$$

Divide 4 by 2 to get 2.

$$x=2$$