Evaluate
\frac{\left(3x+1\right)^{3}}{27}
Expand
x^{3}+x^{2}+\frac{x}{3}+\frac{1}{27}
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x^{3}+x^{2}+\frac{1}{3}x+\frac{1}{27}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+\frac{1}{3}\right)^{3}.
x^{3}+x^{2}+\frac{1}{3}x+\frac{1}{27}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+\frac{1}{3}\right)^{3}.
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