Solve (u+11)^2+6=0

$$( u + 11 ) ^ { 2 } + 6 = 0$$

Solve for u

$$u=-\sqrt{6}i-11\approx -11-2.449489743i$$

$$u=-11+\sqrt{6}i\approx -11+2.449489743i$$

Steps by Finding Square Root

Subtracting 6 from itself leaves 0.

$$\left(u+11\right)^{2}=-6$$

Take the square root of both sides of the equation.

$$u+11=\sqrt{6}i u+11=-\sqrt{6}i$$

Subtract 11 from both sides of the equation.

$$u+11-11=\sqrt{6}i-11 u+11-11=-\sqrt{6}i-11$$

Subtracting 11 from itself leaves 0.

$$u=\sqrt{6}i-11 u=-\sqrt{6}i-11$$

Subtract 11 from i\sqrt{6}.

$$u=-11+\sqrt{6}i$$

Subtract 11 from -i\sqrt{6}.

$$u=-\sqrt{6}i-11$$

The equation is now solved.

$$u=-11+\sqrt{6}i u=-\sqrt{6}i-11$$